| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 36695 | 23刘子淇 | 2023经开区信息技术合格性考试-1 | Python3 | Accepted | 100 | 49 MS | 4476 KB | 149 | 2024-01-02 15:04:27 |
n=int(input()) if 2000<=n<3000: n=0.8*n elif 3000<=n<4000: n=0.7*n elif 4000<=n: n=0.6*n else: n=n print("{:.1f}".format(n))