| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 36753 | 武琪轩 | 2023经开区信息技术合格性考试-1 | Python3 | Accepted | 100 | 40 MS | 4476 KB | 181 | 2024-01-04 14:49:53 |
n=int(input()) m=1 if 3000>n>2000 or n==2000: m*=0.8*n if 4000>n>3000 or n==3000: m*=0.7*n if n>4000 or n==4000: m*=0.6*n if 2000>n: m*=n print('%.1f'%m)