| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 36869 | liuboya1 | 2023经开区信息技术合格性考试-1 | Python3 | Accepted | 100 | 40 MS | 4488 KB | 217 | 2024-01-04 15:38:50 |
a=int(input()) a=float(a) if a<2000: print(a) if 2000<=a<3000: a=0.8*a a1='%.1f'%(a) print(a1) if 3000<=a<4000: a=0.7*a a1='%.1f'%(a) print(a1) if a>=4000: a=0.6*a a1='%.1f'%(a) print(a1)