| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 40266 | 23高尚 | 2023经开区信息技术合格性考试-1 | Python3 | Accepted | 100 | 48 MS | 4476 KB | 160 | 2024-04-09 16:19:51 |
n=int(input()) if 3000> n >= 2000: n=0.8*n if 4000> n >= 3000: n=0.7*n if n >= 4000: n=0.6*n if n <2000: n=n print("%.1f"%n)