Online Judge
| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 50492 | 韩逸宸 | 2023经开区信息技术合格性考试-1 | Python3 | Wrong Answer | 0 | 178 MS | 13564 KB | 141 | 2024-12-24 14:58:19 |
Tests(0/8):
n=int(input()) if 2000<=n<3000: d=n*0.8 elif 3000<=n<4000: d=n*0,7 elif 4000<=n: d=n*0.6 else: d=n print('%.1f'%d)