Run ID 作者 问题 语言 测评结果 分数 时间 内存 代码长度 提交时间
50543 韩逸宸 2023经开区信息技术合格性考试-1 Python3 通过 100 52 MS 4476 KB 530 2024-12-24 15:10:05

Tests(8/8):


def calculate_discount(total_amount): if total_amount < 2000: discount = 0 elif 2000 <= total_amount < 3000: discount = 0.20 # 8折优惠,即20%的折扣 elif 3000 <= total_amount < 4000: discount = 0.30 # 7折优惠,即30%的折扣 else: discount = 0.40 # 6折优惠,即40%的折扣 return total_amount * (1 - discount) # 测试程序 total_amount = float(input()) discounted_price = calculate_discount(total_amount) print(f"{discounted_price:.1f}")


测评信息: