| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 50551 | 大韩子林 | 2023经开区信息技术合格性考试-1 | Python3 | Wrong Answer | 0 | 42 MS | 4452 KB | 144 | 2024-12-24 15:11:37 |
a=float(input()) if a>=2000: b=a*0.8 elif 2000>a>=3000: b=a*0.7 elif 3000>a>=4000: b=a*0.6 else: b=a float(b) print(b)